1+r+3r^2-(2r^2+2r)=

Solution for 1+r+3r^2-(2r^2+2r)= equation:

Simplifying
1 + r + 3r2 + -1(2r2 + 2r) = 0

Reorder the terms:
1 + r + 3r2 + -1(2r + 2r2) = 0
1 + r + 3r2 + (2r * -1 + 2r2 * -1) = 0
1 + r + 3r2 + (-2r + -2r2) = 0

Reorder the terms:
1 + r + -2r + 3r2 + -2r2 = 0

Combine like terms: r + -2r = -1r
1 + -1r + 3r2 + -2r2 = 0

Combine like terms: 3r2 + -2r2 = 1r2
1 + -1r + 1r2 = 0

Solving
1 + -1r + 1r2 = 0

Solving for variable 'r'.

Begin completing the square.

Move the constant term to the right:

Add '-1' to each side of the equation.
1 + -1r + -1 + r2 = 0 + -1

Reorder the terms:
1 + -1 + -1r + r2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1r + r2 = 0 + -1
-1r + r2 = 0 + -1

Combine like terms: 0 + -1 = -1
-1r + r2 = -1

The r term is -1r.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1r + 0.25 + r2 = -1 + 0.25

Reorder the terms:
0.25 + -1r + r2 = -1 + 0.25

Combine like terms: -1 + 0.25 = -0.75
0.25 + -1r + r2 = -0.75

Factor a perfect square on the left side:
(r + -0.5)(r + -0.5) = -0.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.